(x^2)-(4x)+1=-3

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Solution for (x^2)-(4x)+1=-3 equation:


Simplifying
(x2) + -1(4x) + 1 = -3
x2 + -1(4x) + 1 = -3

Remove parenthesis around (4x)
x2 + -1 * 4x + 1 = -3

Multiply -1 * 4
x2 + -4x + 1 = -3

Reorder the terms:
1 + -4x + x2 = -3

Solving
1 + -4x + x2 = -3

Solving for variable 'x'.

Reorder the terms:
1 + 3 + -4x + x2 = -3 + 3

Combine like terms: 1 + 3 = 4
4 + -4x + x2 = -3 + 3

Combine like terms: -3 + 3 = 0
4 + -4x + x2 = 0

Factor a trinomial.
(2 + -1x)(2 + -1x) = 0

Subproblem 1

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Subproblem 2

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Solution

x = {2, 2}

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